Why does running this command give me error message: No such file or directory ?
for i in `find ~/desktop -name '*.py'` ; do ./$i ; done
Why does running this command give me error message: No such file or directory ?
for i in `find ~/desktop -name '*.py'` ; do ./$i ; done
The complete error message makes it much more clear what the problem is:
bash: .//home/youruser/desktop/foo.py: No such file or directory
You can see that there is indeed no such file:
$ .//home/youruser/desktop/foo.py
bash: .//home/youruser/desktop/foo.py: No such file or directory
$ ls -l .//home/youruser/desktop/foo.py
ls: cannot access './/home/youruser/desktop/foo.py': No such file or directory
Here's instead how you can run a file /home/youruser/desktop/foo.py
:
$ /home/youruser/desktop/foo.py
Hello World
So to run it in your loop, you can do:
for i in `find ~/desktop -name '*.py'` ; do $i ; done
Here's a better way of doing the same thing:
find ~/desktop -name '*.py' -exec {} \;
or with a shell loop:
find ~/desktop -name '*.py' -print0 | while IFS= read -d '' -r file; do "$file"; done
For an explanation of what ./
is and does, and why it makes no sense here, see this question
Try find and exec option. http://man7.org/linux/man-pages/man1/find.1.html
-exec command ;
Execute command; true if 0 status is returned. All following
arguments to find are taken to be arguments to the command
until an argument consisting of `;' is encountered. The
string `{}' is replaced by the current file name being
processed everywhere it occurs in the arguments to the
command, not just in arguments where it is alone, as in some
versions of find. Both of these constructions might need to
be escaped (with a `\') or quoted to protect them from
expansion by the shell. See the EXAMPLES section for examples
of the use of the -exec option. The specified command is run
once for each matched file. The command is executed in the
starting directory. There are unavoidable security problems
surrounding use of the -exec action; you should use the
-execdir option instead.
-exec command {} +
This variant of the -exec action runs the specified command on
the selected files, but the command line is built by appending
each selected file name at the end; the total number of
invocations of the command will be much less than the number
of matched files. The command line is built in much the same
way that xargs builds its command lines. Only one instance of
`{}' is allowed within the command, and (when find is being
invoked from a shell) it should be quoted (for example, '{}')
to protect it from interpretation by shells. The command is
executed in the starting directory. If any invocation with
the `+' form returns a non-zero value as exit status, then
find returns a non-zero exit status. If find encounters an
error, this can sometimes cause an immediate exit, so some
pending commands may not be run at all. This variant of -exec
always returns true.
The paths returned by the find
statement will be absolute paths, like ~/desktop/program.py. If you put ./
in front of them, you get paths like ./~/desktop/
which don’t exist.
Replace ./$i
with "$i"
(the quotes to take care of file names with spaces etc.).
You should use $i and not ./$i
I was doing the same thing this exact moment. I wanted a script to find if there's any flac files in the directory and convert it to opus.
Here is my solution:
if test -n "$(find ./ -maxdepth 1 -name '*.flac' -print -quit)"
then
do this
else
do nothing
fi