comparison operator false

Question

var a = '1000';
var b = '200';         

console.log(a > b);=> false

why?

Because you are comparing strings. Remove the single quotes. — aaaaane, Feb 27 '19 at 12:12
Because you compare strings, not int's. Do `console.log(parseInt(a) > parseInt(b))` — Justinas, Feb 27 '19 at 12:12
If the input is in string, try converting them into integer using parseInt and then do the comparison. — Sagar Agrawal, Feb 27 '19 at 12:16

zmag · Accepted Answer · 2019-02-27T12:28:32.727

2

Because you are comparing strings, not numbers.

It compares each character in the same position from the left. So '1' is lower than '2' in character set, it stops comparing and returns false.

console.log('1000' > '200')
// false
console.log(1000 > 200)
// true

edited Feb 27 '19 at 12:28

answered Feb 27 '19 at 12:12

zmag

nó có so sánh độ dài của chuỗi không ?? – Nguyen Duc Duy Feb 27 '19 at 14:25
Could you write it in English again? – zmag Feb 27 '19 at 14:32
thank you . I was understand . – Nguyen Duc Duy Feb 27 '19 at 14:39
does it compare the length of the string ?? i think it compases its string length – Nguyen Duc Duy Feb 27 '19 at 14:40
It does not. `'1000'.length > '200'.length` is comparing the length of the strings. – zmag Feb 28 '19 at 07:22

1 Answers1