How do you calculate the sum of only the first three numbers in a list in Python?

Question

Eg: list = 1, 2, 3… 10

I am trying to solve a question in my course in as simple a way as possible. Sorry if there is already an answer to this question. I couldn't find anything.

Hm, `list[0] + list[1] + list[2]`? – dfsq Mar 01 '19 at 06:46 — dfsq, Mar 01 '19 at 06:46
If you are adding using loops, use three iterations only. – Faraz Jafri Mar 01 '19 at 06:52 — Faraz Jafri, Mar 01 '19 at 06:52

Rahil Hastu · Answer 1 · 2019-03-01T06:58:24.690

2

if a is the list the you can do:

print sum(a[:3])

You can go through the sum() function of python.

Moreover, a[:3] is a slicing operation.

edited Mar 01 '19 at 06:58

answered Mar 01 '19 at 06:48

Rahil Hastu

558
2
13

score 2 · Accepted Answer · answered Mar 01 '19 at 06:48

2

Just use slicing:

mylist = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
result = sum(mylist[:3])

Here, you can easily change 3 to some other number.

See:

answered Mar 01 '19 at 06:48

iz_

15,923
3
25
40

jsky · Answer 3 · 2019-03-01T06:55:06.310

0

The sum function sums numbers in an iterable and is built into Python.

Thus for your situation you can just slice the list and use it.

 numbers = [2.5, 3, 4, -5]

    numbersSum = sum(numbers[:3])
    print(numbersSum)

result is 2.5+3+4=9.5

edited Mar 01 '19 at 06:55

answered Mar 01 '19 at 06:47

jsky

2,225
5
38
54

How do you calculate the sum of only the first three numbers in a list in Python?

3 Answers3