Placing variable in curl request under option -F

Question

I am looking a way to use variable inside "file=@/my/file/path/from/variable/tshootinginfo.txt" in a bash shell on Debian 9.3.

My CURL request:

curl -s -k -D- -u ${user}:${password} -X POST -H "X-Atlassian-Token: nocheck" -F "file=@/my/file/path/from/variable/tshootinginfo.txt" ${jira_subtask}/attachments

I have tried multiple different escapes known to me in a bash, but no much progress. The escape tried:

location_var="/my/file/path/from/variable/tshootinginfo.txt"

-F "file=\"@$location_var\""
-F "file=@\"$location_var\""
-F "file=@\'$location_var\'"
-F "file=@\${location_var}"

Kindly do post whatever you have tried to escape(which you mentioned in your question) with code tags and let us know then. — RavinderSingh13, Mar 01 '19 at 08:37
You're using too many quotes and escapes. Try `-F "file=@${location_var}"` — Gordon Davisson, Mar 01 '19 at 08:49

score 1 · Accepted Answer · answered Mar 01 '19 at 09:04

The argument after -F file=@... is simply a string.

curl -s -k -D- -u "${user}:${password}" \
    -X POST -H "X-Atlassian-Token: nocheck" \
    -F "file=@$my_location_var" \
    "${jira_subtask}/attachments"

You can put braces around the variable name if you like, but it is not necessary in any of these cases. Take care to quote your variables properly, though.

Placing variable in curl request under option -F

1 Answers1