Joining a list in python with different conditions and separator

Question

I have a list of integer

a=[1,2,3,4,5,6,7,8,9]

and i must create a string with the integers separated by spaces and every five number i must add a '\n'

string='1 2 3 4 5\n6 7 8 9\n\n'

I have tried with a join like that:

string=' '.join(a)

but i don't know how to add '\n' with a condition.

you have a single `\n` after 5 digits then `\n\n` after 4 more digits- i don't understand this logic — Chris_Rands, Mar 04 '19 at 21:26
See the duplicate on how to divide a list into chunks of 5. Join the contents of each chunk with spaces, join the chunks with newlines. — Martijn Pieters, Mar 04 '19 at 21:27
@antonio You could also do `from itertools import cycle; string = ''.join(str(item) + sep for item, sep in zip(a, cycle(' '*4 + '\n')))` — Thierry Lathuille, Mar 04 '19 at 21:35

score 1 · Answer 1 · answered Mar 04 '19 at 21:28

1

You can use generator expressions to output the list in chunks for joining:

print('\n'.join(' '.join(map(str, a[i: i + 5])) for i in range(0, len(a), 5)))

This outputs:

1 2 3 4 5
6 7 8 9

answered Mar 04 '19 at 21:28

blhsing

1 Answers1