Java ClientProtocolException exception priority

Asked Mar 05 '19 at 17:35

Active Mar 05 '19 at 17:58

Viewed 68 times

in Java
ClientProtocolException extends IOException
my question is if I want to catch both individually for logging purposes
what should be the order of the catch clause and why?

    } catch (ClientProtocolException e) {
        throw Exception("got ClientProtocolException ")
    } catch (IOException e) {
        throw Exception("got IOException")          
    }

edited Mar 05 '19 at 17:58

asked Mar 05 '19 at 17:35

JavaSheriff

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What you have shown is the correct way. Catch the more specific exception first. What's the issue? – VHS Mar 05 '19 at 17:44
Possible duplicate of https://stackoverflow.com/questions/10964882/order-of-catching-exceptions-in-java – Victor Gubin Mar 05 '19 at 17:47
VHS, I am not sure, there is some confusion, e.getMessage() is empty, and it seems like one catch is catching the other. – JavaSheriff Mar 05 '19 at 17:50
what is i am throwing Exception inside each? will the and i got ClientProtocolException? – JavaSheriff Mar 05 '19 at 17:59

Java ClientProtocolException exception priority

0 Answers0