Spring boot application with two services on two different ports

Question

I have a spring boot application with two services but i need to run one on port 8080 and the other on 8081. Now i'm developing with sts (Spring tool suite) and i run the application with the option "Run as spring boot app", so i don't know where change server configurations. Someone can help me?

Check this duplicated [post](https://stackoverflow.com/questions/21083170/how-to-configure-port-for-a-spring-boot-application) You can do it via application.properties — pbuzulan, Mar 07 '19 at 10:18
I've seen that but i need to put one service in 8080 and another in 8081 with the same application — Alessio Pascucci, Mar 07 '19 at 10:20
Possible duplicate of [How to configure port for a Spring Boot application](https://stackoverflow.com/questions/21083170/how-to-configure-port-for-a-spring-boot-application) — Mickael, Mar 07 '19 at 10:21
It is discussed here: https://stackoverflow.com/questions/36357135/configure-spring-boot-with-two-ports/69190413 — Karmakulov Kirill, Sep 15 '21 at 09:34

score 1 · Accepted Answer · answered Mar 07 '19 at 11:22

1

You can't run two different services under the same spring boot application in two different ports. If you want you can move one service to another spring boot application. But port number will not be same for both services.

answered Mar 07 '19 at 11:22

Pearl

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1

from this [baeldung article](https://www.baeldung.com/spring-boot-context-hierarchy), it seems to be possible to do, using SpringApplicationBuilder API. I have added it as answer also. – Manohar Bhat Mar 22 '23 at 20:21

score 0 · Answer 2 · answered Mar 07 '19 at 12:08

you can configure SprintBoot support two ports.The common method configure is use application.properties or the application.yaml as @Madhu Bhat answer. In SprintBoot to configure another port code like this:

create a connector

        int port = Integer.parseInt(probePort);
        Connector httpConnector = new Connector(HTTP_PROTOCOL);
        httpConnector.setPort(port);
        Http11NioProtocol handler = (Http11NioProtocol) httpConnector.getProtocolHandler();
        handler.setMaxThreads(10);
        handler.setMinSpareThreads(4);
        //handler.setAddress(InetAddress.getLocalHost());
        handler.setAddress(StringTool.getInetAddress());
        return httpConnector;

configure connector to

((TomcatEmbeddedServletContainerFactory) container).addAdditionalTomcatConnectors(connector);

But this need to run two different application onto two different ports? — Alessio Pascucci, Mar 07 '19 at 14:42

score 0 · Answer 3 · answered Apr 06 '21 at 22:22

If you use Docker (most common solution), you can add the port or its full address as an Environment Variable

docker-compose.yml file like this:

application1:
    image: 'application1:latest'
    build:
      context: ./
    container_name: application
    environment:
      - HOST-APP2=localhost:8082
    ports:
      - 8091:8080

application2:
    image: 'application2:latest'
    build:
      context: ./
    container_name: application
    environment:
      - HOST-APP1=localhost:8081
    ports:
      - 8092:8080

or straight in the Dockerfile while building containers

check out here : https://vsupalov.com/docker-arg-env-variable-guide/ it's a good article

score 0 · Answer 4 · answered Mar 22 '23 at 20:20

I have not tried this, but from this baeldung article, it seems to be possible using SpringApplicationBuilder API.

In summary, following are the high level steps

Create 2 properties file with different ports. Refer github repo from article.
Create 2 separate configurations by injecting these properties file.
Use SpringApplicationBuilder to create parent, child or sibling context hierarchy.

krishna T · Answer 5 · 2023-04-09T08:22:22.473

You can create two different child application context's in single application and run two different ports with different services on those ports. Reference : https://www.baeldung.com/spring-boot-context-hierarchy

Following is a sample I used in one of my application.

Main Class of parent context.

package com.kst.gateway;

import org.springframework.boot.WebApplicationType;
import org.springframework.boot.builder.SpringApplicationBuilder;

import com.kst.gateway.inbound.InboundConfig;
import com.kst.gateway.outbound.OutboundConfig;

//@formatter:off
public class GatewayApplication {

    public static void main(String[] args) {
        new SpringApplicationBuilder()
        .parent(GatewayConfig.class)
        .web(WebApplicationType.NONE)
        .child(OutboundConfig.class)
        .web(WebApplicationType.REACTIVE)
        .sibling(InboundConfig.class)
        .web(WebApplicationType.REACTIVE)
        .run(args);
    }
}

Child 1 Configuration :

package com.kst.gateway.inbound;

@Configuration
@ComponentScan("com.kst.gateway.inbound")
@PropertySource("classpath:inbound.properties")
@EnableAutoConfiguration
public class InboundConfig {
    
    @Autowired
    public GatewayConfig config;
    
    @Value("${server.port}")
    public Integer serverPort;
    
    @Bean(name = "issuer_routes")
    public RouteLocator routes(RouteLocatorBuilder routeLocatorBuilder) {
        String issuerUri = config.switchDestinationScheme+"://"+config.switchDestinationIp+":"+config.switchDestinationPort;
        return routeLocatorBuilder.routes()
            .route("issuer_request", routeSpec -> routeSpec
                .remoteAddr(config.npciSourceIps.toArray(new String[0]))
                .and().path("/Req**")
                .uri(issuerUri)
            ).route("acquirer_response", routeSpec -> routeSpec
                .remoteAddr(config.npciSourceIps.toArray(new String[0]))
                .and().path("/Resp**")
                .uri(issuerUri)
            ).build();
    }
}

Child 2 configuration :

package com.kst.gateway.outbound;

@Configuration
@ComponentScan("com.kst.gateway.outbound")
@PropertySource("classpath:outbound.properties")
@EnableAutoConfiguration
public class OutboundConfig {

    @Autowired
    public GatewayConfig config;
    
    @Autowired
    public OutboundRequestUrlFilter acqReqUrlFilter;
    
    @Autowired
    public OutboundResponseUrlFilter acqRespUrlFilter;
    
    @Value("${server.port}")
    public Integer serverPort;
    
    @Bean(name = "acquirer_routes")
    public RouteLocator routes(RouteLocatorBuilder routeLocatorBuilder, NpciEndpointProvider npciEndpointProvider) {
        return routeLocatorBuilder.routes()
            .route("acquirer_request", routeSpec -> routeSpec
                .remoteAddr(config.switchSourceIps.toArray(new String[0]))
                .and().path("/Req**")
                .filters(fs -> fs.filter(acqReqUrlFilter.apply(npciEndpointProvider)))
                .uri("no:/op")
            ).route("issuer_response", routeSpec -> routeSpec
                .remoteAddr(config.switchSourceIps.toArray(new String[0]))
                .and().path("/Resp**")
                .filters(fs -> fs.filter(acqRespUrlFilter.apply(npciEndpointProvider)))
                .uri("no:/op")
            )
            .build();
    }
}

Parent application.properties which will be inherited by both the child context's

spring.application.name=gateway
server.ssl.key-store=classpath:ssl.pfx
server.ssl.key-store-password=Ippb@2023
server.ssl.key-store-type=pkcs12
server.ssl.key-alias=ssl
spring.cloud.gateway.httpclient.ssl.use-insecure-trust-manager=true
spring.cloud.service-registry.auto-registration.enabled=false
spring.cloud.discovery.enabled=false
spring.cloud.config.discovery.enabled=false

Child 1 inbound.properties file

spring.application.name=inbound
server.port=8443

Child 2 outbound.properties file

spring.application.name=outbound
server.port=443

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Madhu Bhat · Answer 6 · 2019-03-07T12:46:42.637

-1

The port can be defined on the application.properties or the application.yaml configuration file that you use.

In application.properties file, define it as below:

server.port=8090

Or in case you are using a application.yaml config, define it as below:

server:
    port: 8090

edited Mar 07 '19 at 12:46

answered Mar 07 '19 at 10:18

Madhu Bhat

13,559
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So, if i need to access two different ports i need to run the application on two server placed on two different ports? – Alessio Pascucci Mar 07 '19 at 10:40
1

@AlessioPascucci in case you must have two services on different ports, you need to run it as two different applications, each with it's own different port. – Madhu Bhat Mar 07 '19 at 11:05

score -3 · Answer 7 · answered Mar 07 '19 at 10:19

-3

you can write below line in application.properties or application.yml

server.port=8080

answered Mar 07 '19 at 10:19

vivekdubey

484
2
7

score -3 · Answer 8 · answered Mar 07 '19 at 10:23

-3

Sure. You can do it in the application.properties file of spring boot project via setting server.port=number for each service.

answered Mar 07 '19 at 10:23

Emin Javadov

140
1
8

Spring boot application with two services on two different ports

8 Answers8