What's wrong in this code?It terminates just before second cin can execute

Question

#include<iostream>
#include<vector>
#include<ios>
#include<limits>
int main()
{
     using namespace std;
     vector<string> disliked,words;
     int n;
     cout<<"Enter the word that you dislike."<<endl;
     for(string word;cin>>word;)
         disliked.push_back(word);
     cout<<"Enter the list of words."<<endl;
     cin.sync();
     for(string word;cin>>word;)
         words.push_back(word);
     for(int i=0;i<words.size();i++)
     {
         int n=0;
         for(int j=0;j<disliked.size();j++)
         {
             if(disliked[j]==words[i])
                 n++;
         }
         if(n==0)
         cout<<words[i]<<endl;
     }
     cout<<"Program completed."<<endl;
     return 0;
}

Write a program to bleep out the word that you don't like.First input the list of words that you don't like. Program terminates after printing "Enter list of words."

Answer 1

Instead of cin.sync() use cin.clear();

You may also need to use cin.ignore() also.

The problem is you have a ^D stuck in cin and it's blocking any future cin entries. Control D closes the system pipe. And the program immediately exits.

It might be more usable if you check for an input that ends the input list.

Execution using cin.sync():

$ ./a.out 
Enter the word that you dislike.
test
a
b
c
^d
Enter the list of words.
Program completed.
$ 

Execution after replacing cin.sync() with adding cin.clear() and cin.ignore():

$ ./a.out 
Enter the word that you dislike.
test
a
b
c
^d
Enter the list of words.
a
b
c
^d
Program completed.
$