Is it possible to have multiple tries, with only one catch

Question

I'm adding multiple players to a team and each individual player needs a try catch, but the catch is always the same

try{
    team.addPlayer( new Player( 1, "PLYR1" ) );
} catch ( Exception e ){
     System.out.println( e.toString() );
}

try {
     team.addPlayer( new Player( 2, "PLYR2" ) );
} catch ( Exception e ){
     System.out.println( e.toString() );
}

Is there any way to simplify this?

You can add the players in the same `try` clause, and have only one `catch`. — Maroun, Mar 08 '19 at 11:08
The answer is yes, but the exact way you would do it depends on what behaviour you want. For example, if adding player 1 fails do you want to try adding player 2 or do you want to stop? — Steve Bosman, Mar 08 '19 at 11:12
Possible duplicate of [Multiple or Single Try Catch](https://stackoverflow.com/questions/4555322/multiple-or-single-try-catch) — Googlian, Mar 08 '19 at 11:14

score 1 · Answer 1 · answered Mar 08 '19 at 11:16

as saying at your comments you can use this

try{
    team.addPlayer( new Player( 1, "PLYR1" ) );
    team.addPlayer( new Player( 2, "PLYR2" ) );
} catch ( Exception e ){
     System.out.println( e.toString() );
}

of if you care about if the first player is added, use this:

try{
    team.addPlayer( new Player( 1, "PLYR1" ) );
    try {
         team.addPlayer( new Player( 2, "PLYR2" ) );
    } catch ( Exception e ){
         System.out.println( e.toString() );
    }
} catch ( Exception e ){
     System.out.println( e.toString() );
}

score 1 · Answer 2 · answered Mar 08 '19 at 11:21

1

you can try this code instead of using two try blocks.

try{
    team.addPlayer( new Player( 1, "PLYR1" ) );
     team.addPlayer( new Player( 2, "PLYR2" ) );
} 
catch ( Exception e ){
     System.out.println( e.toString() );
}

answered Mar 08 '19 at 11:21

Pallu

11
2

score 0 · Accepted Answer · answered Mar 08 '19 at 11:53

If you want to iterate through all possible players using catch and throw the same error to stdout if an exception occurs you should use a basic for loop.

Player class is assumed to be defined and team object created:

String[] players = {"PLYR1", "PLYR2", "PLYR3"}

for (String player: players) {
  try{
      team.addPlayer( new Player( 1, player ) );
  } catch ( Exception e ){
       System.out.println( e.toString() );
  }
}

Is it possible to have multiple tries, with only one catch

3 Answers3