What is the shortest and simplest way to get a random integer in C++?

Question

I would like to get a random integer between 1 and 10 in C++ using the least amount of code possible, with the start and stop values being inclusive.

I'm aware of the rand() function, but how can I use it to get an integer in this range?

Thank you!

try something like this `rand()%10+1;` – seccpur Mar 10 '19 at 03:37 — seccpur, Mar 10 '19 at 03:37

score 1 · Accepted Answer · edited Mar 10 '19 at 05:57

1

You can generate a random integer between 1 and 10 (inclusive) with this piece of code

int i = rand()%10+1;

//rand()%10 get a random int between 0 to 9
//and what you should do next is +1

edited Mar 10 '19 at 05:57

Jacky Huynh

answered Mar 10 '19 at 03:37

Matisse

1

Also mention the fact that rand() will give the same number no matter how many times you recompile the program – Hemil Mar 10 '19 at 05:48

score 0 · Answer 2 · answered Mar 10 '19 at 03:30

0

you can check out this article which details precisely how to obtain random integers.

int i = rand()%8+2;

should give you random integers between 1 and 10 both exclusive

answered Mar 10 '19 at 03:30

TheRealOrange

Thanks, but I was looking for inclusive. Sorry, that's my fault for not clarifying. – Ben Soyka Mar 10 '19 at 03:44

2 Answers2