A way to sort integers in a list by using a dictionary

Question

I was wondering if there would be a way to sort a list in order according to the increasing floats as values in a dictionary. I don't really know how to explain it so I'll demonstrate what I mean

[3, 6, 4]

to

[6, 4, 3]

with dictionary like this

{6: 15.6, 3: 120.0, 4: 17.3}

Possible duplicate of [How do I sort a dictionary by value?](https://stackoverflow.com/questions/613183/how-do-i-sort-a-dictionary-by-value) — j-i-l, Mar 12 '19 at 00:14
Try using an `OrderedDict` from the `collection` module: https://docs.python.org/3/library/collections.html#collections.OrderedDict — ScottMcC, Mar 12 '19 at 00:15

score 6 · Accepted Answer · answered Mar 12 '19 at 00:16

6

Use the key argument of sorted:

>>> mylist = [3, 6, 4]
>>> mydict = {6:15.6, 3:120.0, 4:17.3}
>>> sorted(mylist, key=mydict.get)
[6, 4, 3]

answered Mar 12 '19 at 00:16

ekhumoro

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score 0 · Answer 2 · answered Mar 12 '19 at 00:31

0

For your example, you don't even need that list as the dict keys are sufficient:

>>> my_dict = {6: 15.6, 3: 120.0, 4: 17.3}
>>> sorted(my_dict, key=my_dict.get)
[6, 4, 3]

answered Mar 12 '19 at 00:31

Selcuk

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A way to sort integers in a list by using a dictionary

2 Answers2