Please note this is not a duplicate question. This question involves submitting a form and refreshing a div on a change event - not a click event. FYI.
I have a form to allow users to upload an image. I have removed the submit button and added a javascript on change event to submit the form automatically when the user inputs an image.
This works fine and the image is uploaded.
However, I am also pulling through the image to display this to the user. At the moment, the user does not see the image change until they refresh the page or sometimes not even until they clear their cache.
The div containing the images should refresh upon the form being submitted, and the page itself should not refresh. At the moment the div is not refreshing and I think the form is submitting and refreshing the page.
Please can someone show me where I am going wrong? Thanks
Code:
<!-- Commence Photo Upload A -->
<?php
if(isset($_FILES['image6'])){
$dir = $image .'/F/';
$file_name = $_FILES['image6']['name'];
$file_name = $dir. 'sub_img.jpg';
$file_size = $_FILES['image6']['size'];
$file_tmp = $_FILES['image6']['tmp_name'];
$file_type = $_FILES['image6']['type'];
$tmp = explode('.',$_FILES['image6']['name']);
$file_ext=strtolower(end($tmp));
$extensions= array("jpeg","jpg","png","gif");
if(in_array($file_ext,$extensions)=== false){
$errors[]="extension not allowed, please choose a GIF, JPEG or PNG file.";
}
if($file_size > 2097152) {
$errors[]='File size must be excately 2 MB';
}
if(empty($errors)==true) {
move_uploaded_file($file_tmp, $file_name);
}else{
}} ?>
<script>
$('#uploads6').submit(function(){
var data = $(this).serialize();
$.ajax({
url: "upload_6.php",
type: "POST",
data: data,
success: function( data )
{
//here is the code I want to refresh the div(#container)
$('.image6').html(data);
},
error: function(){
alert('ERROR');
}
});
return false;
});
</script>
<form id="uploads6" action = "" method = "POST" enctype = "multipart/form-data">
<label class="profile_gallery_image_in"><input type="file" name="image6" id="image6" onchange="form.submit()"/><p class="label"></p><img class="myImg" src="<?php echo $image.'/F/sub_img.jpg'; ?>" height="100%" width="100%" /></label>
</form>