JS find multiple values in array

Question

I have an array which the values are :

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26

then i want to check this values to the array :

14,15,16,17

i tried with this but didn't work :

function contains(a, toFind) {
    for (var i = 0; i < a.length; i++) {
        if (equalArray(a[i], toFind)) {
            return true;
        }
    }
    return false;
}

function equalArray(a, b) {
    if (a.length === b.length) {
        for (var i = 0; i < a.length; i++) {
            if (a[i] !== b[i]) {
                return false;
            }
        }
        return true;
    } else {
        return false;
    }
}

Anyone can help me out ?

The code you are using would only work if both were arrays of arrays. — Luca Kiebel, Mar 14 '19 at 11:10
What does *"then i want to check this values to the array"* mean? You want to see if it has *any* of them? *All* of them? In that order? In any order? Consecutively? — T.J. Crowder, Mar 14 '19 at 11:10
SOLVED [https://stackoverflow.com/questions/9204283/how-to-check-whether-multiple-values-exist-within-an-javascript-array](https://stackoverflow.com/questions/9204283/how-to-check-whether-multiple-values-exist-within-an-javascript-array) — 0x00b0, Mar 14 '19 at 11:11

score 0 · Accepted Answer · answered Mar 14 '19 at 11:12

0

use includes.

let a = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26];

console.log(a.includes(14));
console.log(a.includes(15));
console.log(a.includes(16));
console.log(a.includes(17));

answered Mar 14 '19 at 11:12

Stanimirovv

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JS find multiple values in array

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