How to compare two array based on matched values and order in PHP?

Question

I have 2 array, I want to compare them by matched values and order and count of total eligible values.

$a = [A,B,C,D,E,F,G];
          | |     |
$b = [B,A,C,D,F,E,G];

In this case the output should be 3 . How can I achieve this with top performance?

Update:

I am not asking matched values only , values should matched at the same order as well.

Possible duplicate of [Php match values between 2 arrays](https://stackoverflow.com/questions/8038989/php-match-values-between-2-arrays) — Mayank Vadiya, Mar 15 '19 at 09:21
I think this should do it `$result = array_intersect($a, $b); print_r(count($result));` — executable, Mar 15 '19 at 09:21

score 1 · Accepted Answer · answered Mar 15 '19 at 09:31

Array_diff_assoc will count what is not the same (4).
Count will count the number of items (7).
7-4 = 3.

echo count($a) - count(array_diff_assoc($a,$b)); // 3

Edit or just array_intersect_assoc

echo count(array_intersect_assoc($a,$b)); //3

Didn't cross my mind until now.

Mihai Matei · Answer 2 · 2019-03-15T09:28:08.840

0

Assuming that both arrays have the same size you can do it with a simple loop:

$count = 0;

foreach ($a as $key => $value) {
    if ($value === $b[$key]) {
        $count++;
    }
}

var_dump($count);

If they have different sizes then you must check if the key exists in the second array too.

edited Mar 15 '19 at 09:28

answered Mar 15 '19 at 09:20

Mihai Matei

2 Answers2