JavaScript string .replace for URL

Question

I scrape sites for a database with a chrome extension, need assitance with a JavaScript Clean up function

e.g

https://www.alibaba.com/product-detail/_60789694386.html?spm=a2700.galleryofferlist.normalList.1.5be41470uWBNGm&s=p

my target output is:

_60789694386.html

everything past .html needs to be removed, but since it is diffrent in each URL - i'm lost

the output is in a .csv file, in which i run a JavaScript to clean up the data.

   this.values[8] = this.values[8].replace("https://www.alibaba.com/product-detail/","");

this.values[8] is how i target the column in the script. (Column 8 holds the URL)

you could split at `?` and get the first bit. `yourString.split('?')[0]` ? — iacobalin, Mar 15 '19 at 13:41
This could be helpful **[Remove query string]** [https://stackoverflow.com/remove-querystring-from-url ](https://stackoverflow.com/questions/2540969/remove-querystring-from-url) — ejaz, Mar 15 '19 at 13:49

score 3 · Accepted Answer · edited Jan 16 '20 at 17:25

3

Well, you can use split.

var final = this.values[8].split('.html')[0]

split gives you an array of items split by a string, in your case'.html', then you take the first one.

edited Jan 16 '20 at 17:25

Mickael B.

4,755
4
24
48

answered Mar 15 '19 at 13:42

Raul Rene

10,014
9
53
75

score 1 · Answer 2 · answered Mar 15 '19 at 13:42

1

Consider using substr

this.values[8] = this.values[8].substr(0,this.values[8].indexOf('?'))

answered Mar 15 '19 at 13:42

Gwyn Rees

11
3

score 0 · Answer 3 · answered Mar 15 '19 at 13:41

You can use split method to divide text from ? as in example.

var link = "https://www.alibaba.com/product-detail/_60789694386.html?spm=a2700.galleryofferlist.normalList.1.5be41470uWBNGm&s=p"
var result = link.split('?')[0].replace("https://www.alibaba.com/product-detail/","");
console.log(result);

score 0 · Answer 4 · answered Mar 15 '19 at 13:43

0

Not sure i understood your problem, but try this

var s = 'https://www.alibaba.com/product-detail/_60789694386.html?spm=a2700.galleryofferlist.normalList.1.5be41470uWBNGm&s=p'
s = s.substring(0, s.indexOf('?'));
console.log( s );

answered Mar 15 '19 at 13:43

Hassan ALAMI

318
1
5
18

score 0 · Answer 5 · answered Mar 15 '19 at 13:45

0

For when you don't care about readability...

this.values[8] = new URL(this.values[8]).pathname.split("/").pop().replace(".html","");

answered Mar 15 '19 at 13:45

Niet the Dark Absol

320,036
81
464
592

score 0 · Answer 6 · answered Mar 15 '19 at 13:48

Alternate, without using split

var link = "https://www.alibaba.com/product-detail/_60789694386.html?spm=a2700.galleryofferlist.normalList.1.5be41470uWBNGm&s=p"
var result = link.replace('https://www.alibaba.com/product-detail/', '').replace(/\?.*$/, '');
console.log(result);

score 0 · Answer 7 · answered Mar 15 '19 at 13:53

You can use the regex to get it done. As of my knowledge you do something like:

    var v = "https://www.alibaba.com/product-detail/_60789694386.html?spm=a2700.galleryofferlist.normalList.1.5be41470uWBNGm&s=p"
    result = (v.match(/[^\/]+$/)[0]);
    result = result.substring(0,result.indexOf('?'));
    console.log(result);    // will return _60789694386.html

JavaScript string .replace for URL

7 Answers7