Can I somehow create a function that looks like .toUpperCase()?

Question

Instead of using

function functionName(arg){
arg = 1;
}
name(arg);

I want to use something like the .toUppercase() function

function functionName(){
this = 1;
}
arg.name();

Is this possible?

Your question make zero sense to me. Can you try to rephrase it? — idmean, Mar 15 '19 at 16:42
https://developer.mozilla.org/en-US/docs/Learn/JavaScript/Objects/Object_prototypes — j08691, Mar 15 '19 at 16:43
I really can't get what you mean but you may mean somthing like arg.toString().toUpperCase() — Michel Hanna, Mar 15 '19 at 16:44
Possible duplicate of [How do I write an extension method in JavaScript?](https://stackoverflow.com/questions/9354298/how-do-i-write-an-extension-method-in-javascript) — adiga, Mar 15 '19 at 17:32

score 1 · Accepted Answer · answered Mar 15 '19 at 16:45

1

You can extend the prototype of the string object in JavaScript

String.prototype.functionName = function () {
    return this; //do whatever you want to do it with the string
};

Now you are able to call this way mystring.functionName()

answered Mar 15 '19 at 16:45

OsDev

1

While it's true that it's possible to do that, you shouldn't _ever_ have to do that. – Mar 15 '19 at 16:50
1

This is exactly what I wanted, thank you. @davmich its not about it being optimized, recommended or conventional. Its just to prove a point and I just wanted to know if it is possible. – KaZMa Mar 15 '19 at 16:55

score 1 · Answer 2 · answered Mar 15 '19 at 16:46

1

add function inside the object

var arg = {
  name:function(str){
    return str;
  }
}

console.log(arg.name('sss'))

answered Mar 15 '19 at 16:46

prasanth

2 Answers2