Converting an array of integers into an array of binary code in Python

Question

I'm new in Python and need to convert an array of integers into one in binary code.

s_str = "test"    
s_acii = [ord(c) for c in s_str]
print(s_acii)
>> [116, 101, 115, 116]

What I need:

>> [1110100, 1100101, 1110011, 1110100]

Thanks!

Let me get this straight: You want decimal numbers that *look* like binary numbers? Are you sure you don't want the binary numbers as strings? — Aran-Fey, Mar 18 '19 at 18:57
Try `list(map(bin,s_acii))` or `[x.lstrip('0b') for x in map(bin,s_acii)]` — mad_, Mar 18 '19 at 18:58
I'm voting to close this question as off-topic because we don't write code for you. Show us what you have tried — user1251007, Mar 18 '19 at 18:58

score 1 · Accepted Answer · answered Mar 18 '19 at 18:58

1

You can use bin built-in function to convert the integers into their binary representations:

>>> l = [116, 101, 115, 116]
>>> [bin(i) for i in l]
['0b1110100', '0b1100101', '0b1110011', '0b1110100']

If you do not want the 0b prefix, use string formatting with binary integer representation:

>>> l = [116, 101, 115, 116]
>>> ["{0:b}".format(i) for i in l]
['1110100', '1100101', '1110011', '1110100']

answered Mar 18 '19 at 18:58

kalehmann

Thanks a lot, works fine! I tried the format function but used it wrongly. – mafehx Mar 18 '19 at 19:22

score 0 · Answer 2 · answered Mar 18 '19 at 19:02

0

You can use the str.format method with b as the presentation type:

print('[{}]'.format(', '.join(map('{:b}'.format, s_acii))))

This outputs:

[1110100, 1100101, 1110011, 1110100]

answered Mar 18 '19 at 19:02

blhsing

2 Answers2