convert curl get to rest api to python

Question

I have this curl command:

curl -X GET --header 'Accept: application/vnd.pagerduty+json;version=2' --header 'Authorization: Token token=y_NbAkKc66ryYTWUXYEu' 'https://api.pagerduty.com/services?time_zone=UTC&sort_by=name'

I need to convert it to python using requests library

import requests

def support(self): 
    services_list = requests.get('I need to convert the link to pass it here as a parameter')

2

https://curl.trillworks.com/ – stx101 Mar 21 '19 at 11:45

score 2 · Accepted Answer · edited Mar 21 '19 at 16:53

2

import requests

def support():
    headers = {
        'Accept': 'application/vnd.pagerduty+json;version=2',
        'Authorization': 'Token token=y_NbAkKc66ryYTWUXYEu'}

    payloads = (
        ('time_zone', 'UTC'),
        ('sort_by', 'name'),)

    services_list = requests.get('https://api.pagerduty.com/services', headers=headers, params=payloads)

edited Mar 21 '19 at 16:53

DirtyBit

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answered Mar 21 '19 at 11:46

Nordle

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convert curl get to rest api to python

1 Answers1