How to print out value and name of each arg from a splat argument list

Question

I have

a = 'a string'
b = 3

I use this common pattern:

puts "a: #{a}, b: #{a}"

I would like to do this with a method e.g.,

def puts_auto(*args)
  str = args.map { |arg| "#{arg.object_name #{a}" }.join('')
  puts str
end

where object_name finds the name of the object that was used to create the arg. Is there such method like object_name? Is there a way to print the value and the name of each argument from a splat argument list?

Sorry, but what is your question really? I don’t see how variable assignments are related to splat parameters. — idmean, Mar 21 '19 at 21:44
Does this https://stackoverflow.com/a/49121443/1779477 answer your question? — idmean, Mar 21 '19 at 21:45
The comment I just posted disappeared. Why? Who? It merely said that I thought @idmean's question should be answered in the affirmative. — Cary Swoveland, Mar 21 '19 at 21:54
Possible duplicate of [Ruby - print the variable name and then its value](https://stackoverflow.com/questions/2603617/ruby-print-the-variable-name-and-then-its-value) — Mark, Mar 21 '19 at 22:04

Obromios · Accepted Answer · 2019-03-22T03:58:08.027

0

Using Mark's suggestion in regard to this SO question, the following works

  def puts_auto (*args, &b)
    str = args.map { |arg| "#{arg} = #{eval(arg.to_s, b.binding)}" }.join(', ')
    puts str
  end

so

puts_auto(:a, :b){} # outputs `a = a string, b = 3`

edited Mar 22 '19 at 03:58

answered Mar 21 '19 at 23:14

Obromios

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How to print out value and name of each arg from a splat argument list

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