Jest unit test - How do I call through async function in a setTimeout repeating function

Question

UPDATE: Safe to say this is basically a duplicate of Jest: Timer and Promise don't work well. (setTimeout and async function)

I have a function that repeats itself after performing an asynchronous function. I want to verify that jest.advanceTimersOnTime(5000) continues to yield expect(doAsyncStuff).toHaveBeenCalledTimes(X);.

I observe that we can reach the call to repeat the function but it does not "go through" when asking jest to advance timers. It does work when you remove the async function preceding it. So it sounds like I have to get doAsyncStuff to "call through" or resolve some pending promise here?

Function

function repeatMe() {
    setTimeout(() => {
        doAsyncStuff.then((response) => {
            if (response) {
                console.log("I get here!");
                repeatMe();
            }
        })
    }, 5000);
}

Test

jest.useFakeTimers();

let doAsyncStuff = jest.spyOn(updater, 'doAsyncStuff');
doAsyncStuff.mockResolvedValue(true);

repeatMe();

jest.advanceTimersByTime(5000);
expect(doAsyncStuff).toHaveBeenCalledTimes(1);

jest.advanceTimersByTime(5000);
expect(doAsyncStuff).toHaveBeenCalledTimes(2); // Failed?

score 3 · Accepted Answer · answered Mar 22 '19 at 17:03

So it sounds like I have to...resolve some pending promise here?

Yes, exactly.

The short answer is that a Promise callback gets queued in PromiseJobs by the then chained to the Promise returned by doAsyncStuff, and the way the test is written, that callback never has a chance to run until the test is already over.

To fix it, give the Promise callbacks a chance to run during your test:

updater.js

export const doAsyncStuff = async () => { };

code.js

import { doAsyncStuff } from './updater';

export function repeatMe() {
  setTimeout(() => {
    doAsyncStuff().then((response) => {
      if (response) {
        console.log("I get here!");
        repeatMe();
      }
    })
  }, 5000);
}

code.test.js

import * as updater from './updater';
import { repeatMe } from './code';

test('repeatMe', async () => {
  jest.useFakeTimers();

  let doAsyncStuff = jest.spyOn(updater, 'doAsyncStuff');
  doAsyncStuff.mockResolvedValue(true);

  repeatMe();

  jest.advanceTimersByTime(5000);
  expect(doAsyncStuff).toHaveBeenCalledTimes(1);  // Success!

  await Promise.resolve();  // let callbacks in PromiseJobs run

  jest.advanceTimersByTime(5000);
  expect(doAsyncStuff).toHaveBeenCalledTimes(2);  // Success!

  await Promise.resolve();  // let callbacks in PromiseJobs run

  jest.advanceTimersByTime(5000);
  expect(doAsyncStuff).toHaveBeenCalledTimes(3);  // Success!

  // ... and so on ...
});

The complete details of exactly what happens and why can be found in my answer here

score 0 · Answer 2 · answered Mar 22 '19 at 15:25

Apparently Jest troubleshooting references this issue: we have set the definition to happen asynchronously on the next tick of the event loop. I guess this applies to events within the live code too, not just the written tests.

Doing jest.runAllTimers() will set things into an endless loop.

Adding jest.runAllTicks() will advance the tick so the above tests now work.

I'm still confused but I guess this is the answer.

jest.advanceTimersByTime(5000);
jest.runAllTicks();
expect(doAsyncStuff).toHaveBeenCalledTimes(1);

jest.advanceTimersByTime(5000);
jest.runAllTicks();
expect(doAsyncStuff).toHaveBeenCalledTimes(2);

https://jestjs.io/docs/en/troubleshooting#defining-tests

Also required for this to work is to mock the implementation of doAsyncStuff because whatever async stuff inside doAsyncStuff also I think gets queued into the tick events.

            doAsyncStuff.mockImplementation(() => {
                return new Promise.resolve();
            });

Jest unit test - How do I call through async function in a setTimeout repeating function

Function

Test

2 Answers2