How can I use JSONDecoder / Codable with this date format?

Question

I get the following date back from an API.

{
  "createdDate": "2019-03-22T15:53:06.663Z"
}

I'd like to decode this and store it as a Date type.

My JSONDecoder is not able to decode this however.

I have tried to extend it with

extension DateFormatter {
    static let iso8601Full: DateFormatter = {
        let formatter = DateFormatter()
        formatter.dateFormat = "yyyy-MM-dd'T'HH:mm:ss.SSSZ"
        formatter.calendar = Calendar(identifier: .iso8601)
        formatter.timeZone = TimeZone(secondsFromGMT: 0)
        formatter.locale = Locale(identifier: "en_US_POSIX")
        return formatter
    }()
}

and then using decoder.dateDecodingStrategy = .formatted(DateFormatter.iso8601Full) but this does not work

**What** does not work? Actually `JSONDecoder` is a bit overkill for a dictionary with one key-value pair. — vadian, Mar 23 '19 at 17:22
I'm only including the relevant props, there is a lot more included. — Tim J, Mar 23 '19 at 17:28

score 2 · Accepted Answer · answered Mar 23 '19 at 17:27

2

Use ISO8601DateFormatter with formatting options

let str = "2019-03-22T15:53:06.663Z"
let formatter = ISO8601DateFormatter()
formatter.formatOptions = [.withFullDate, .withFullTime, .withTimeZone, .withFractionalSeconds]
let date = formatter.date(from: str)

answered Mar 23 '19 at 17:27

Joakim Danielson

43,251
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1

or simply `[.withInternetDateTime, .withFractionalSeconds]`. Btw you can't use ISO8601DateFormatter with `dateDecodingStrategy`. You would need to create a custom Date decoding strategy. https://stackoverflow.com/questions/28016578/how-to-create-a-date-time-stamp-and-format-as-iso-8601-rfc-3339-utc-time-zone/28016692#28016692 – Leo Dabus Mar 23 '19 at 21:57

How can I use JSONDecoder / Codable with this date format?

1 Answers1