Passing arguments to around_action raises: LocalJumpError no block given (yield)

Question

I want to wrap my action in this around_action:

around_action { do_stuff("foo") }

My around_action looks like this:

def do_stuff(arg)
  some_block do
    Rails.logger.error "arg: #{arg}"
    yield
  end
end

But this raises a LocalJumpError no block given (yield). What am I doing wrong?

Checkout https://stackoverflow.com/a/20561223/398863 where you will find different ways to specify block in `around_action` — Amit Patel, Mar 25 '19 at 11:38
This should help you - https://stackoverflow.com/a/18623495/4614833 — Sinscary, Mar 25 '19 at 12:04
Sorry, but I've tried various approaches based on the answers you both linked to, but none works. — JohnSmith1976, Mar 25 '19 at 13:44
Basically you are not passing any block to the `do_stuff` method so you are getting [LocalJumpError](https://ruby-doc.org/core-2.3.0/LocalJumpError.html). I don't understand the purpose of `do_stuff`. Is this method being called from elsewhere other than `around_filter`? — Amit Patel, Mar 25 '19 at 18:26
@AmitPatel the `do_stuff` is just an example, but in order to not distract I've left it simple and useless. But if you're saying I'm not passing any block, please show me how to do that. — JohnSmith1976, Mar 25 '19 at 19:20

score 1 · Accepted Answer · answered Mar 26 '19 at 09:50

1

I ended up solving it with:

around_action -> (controller, block) { do_stuff("foo", block) }

def do_stuff(arg, block)
  some_block do
    Rails.logger.error "arg: #{arg}"
    block.call
  end
end

answered Mar 26 '19 at 09:50

JohnSmith1976

536
2
12
35

score 0 · Answer 2 · answered Feb 14 '23 at 22:25

0

I had the same issue but eventually found this to work:

around_action do :something

def something
  begin
    FOOBAR
    yield
  end
end

answered Feb 14 '23 at 22:25

Matt16749

119
11

Passing arguments to around_action raises: LocalJumpError no block given (yield)

2 Answers2