How to remove all occurences of a string with `/` from another string

Question

I have string which looks like this:

/mnt/blumeta0/db2/head/home/db2inst1/sqllib/ctrlha/ /mnt/blumeta0/db2/head/home/db2inst1/sqllib/ctrl/ /mnt/blumeta0/db2/head/home/db2inst1/sqllib/log/ /mnt/blumeta0/db2/head/home/db2inst1/sqllib/cfg/

This is stored in variable sqllib_files_folders in the script below : I am trying to remove all occurences of prefix TMP_SOTRAGE which is /mnt/blumeta0/db2 for which I wrote the following:

#!/bin/sh
TMP_STORAGE="/mnt/blumeta0/db2"
METADATA_PATH="/head"
sqllib_files_folders=$(find $TMP_STORAGE$METADATA_PATH/home/db2inst1/sqllib/ -maxdepth 1 -mindepth 1 '(' '(' -type d -printf '%p/ ' ')' -o -printf '%p ' ')')
sqllib_files_folders=echo ${sqllib_files_folders//$TMP_STORAGE/}
echo $sqllib_files_folders

This works for string which does not have /. I have tried escaping with \. But that does not work either. Any help please?

You should store the paths in an array instead of relying on them not containing spaces, see https://stackoverflow.com/questions/23356779/how-can-i-store-the-find-command-results-as-an-array-in-bash — Benjamin W., Mar 25 '19 at 14:50

score 1 · Accepted Answer · answered Mar 25 '19 at 14:42

1

For example:

sqllib_files_folders=$(echo $sqllib_files_folders|sed "s%$TMP_STORAGE%%g")

answered Mar 25 '19 at 14:42

Alexey Godin

307
1
6

score 1 · Answer 2 · answered Mar 25 '19 at 14:45

2 ideas come to mind:

cd to the directory first so the prefix is not in the find output in the first place:

sqllib_files_folders=$(cd "$TMP_STORAGE" && find ./"$METADATA_PATH"/home/db2inst1 ...)

backslash escape the slashes for the parameter expansion replacement (this one's a mouthful):

sqllib_files_folders=${sqllib_files_folders//${TMP_STORAGE//\//\\/}/}
# ...........................................^^...........^^^^^^^^^

How to remove all occurences of a string with `/` from another string

2 Answers2