Python Check if Methods or interface is implemented before runtime

Question

I'm creating an interface Mixins that contains methods that will throw error if it is not implemented, however it only happens during run time when the method is called, i would like to have python check if method is implemented before run time.

class TestInterface():
    def get_testing_name(self):
        raise NotImplementedError

    def do_something(self):
        return self.get_testing_name()


class Testing(TestInterface):
    def __init__(self):
        super().do_something()

In my Testing class, i didn't defined get_testing_name method, hence it will raise NotImplementedError. However this will only happen on run time

How do i make sure python check if method is not implemented before run time?

this may be related: https://stackoverflow.com/questions/44576167/force-child-class-to-override-parents-methods/44576235#44576235 — hiro protagonist, Mar 27 '19 at 07:05
If it is before runtime, then probably it should be done by the IDE? In such a case, most of the IDE could inspect whether an abstract method is implemented. — M Ciel, Aug 16 '22 at 03:22

score 0 · Answer 1 · answered Mar 27 '19 at 07:08

0

I don't know if I understood you. Maybe that was what you wanted ?:

try:
    t = Testing()
except NotImplementedError:
    print("Fail")

answered Mar 27 '19 at 07:08

Mikey

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Python Check if Methods or interface is implemented before runtime

1 Answers1