Implementing new window on combo box

Question

i want to implement and open new window when i choose one entry from drop down list. However when I use getSelectedItem in if / else - it compile but returning errors when want to choose entry in application. Where is the problem ?

public class TemplatesList extends JComboBox<String>
{
    public String[] lista = {"change request", "emergancy change request", "problem request","problem handover", "Major Incident handover" };
    public JComboBox faceCombo;
    String e;


    public TemplatesList()
    {
        //faceCombo = new JComboBox();
        for (int i=0; i < lista.length; i++)
        {
            this.addItem(lista[i]);
        }
        addActionListener(new ActionListener() {
            public void actionPerformed(ActionEvent e) {
            if (faceCombo.getSelectedItem() == "change request"){
                SecondWindow regFace = new SecondWindow();
                regFace.setVisible(true);
            } else {

            }
        }
    });
    }
}

Good to refer: https://stackoverflow.com/questions/32750611/gui-jcombobox-and-opening-a-new-window — Mebin Joe, Mar 27 '19 at 11:17
Don't use `==` when comparing objects (strings in your case) — Robert Kock, Mar 27 '19 at 11:18
Your `TemplatesList` is the actual combo. Why are you refering to `faceCombo` within the actionListener? — Robert Kock, Mar 27 '19 at 11:21
good point, when i remove faceCombo from (faceCombo.getSelectedItem() == "change request") it works perfectly. — Tomasz Kostrzewski, Mar 27 '19 at 11:33
Possible duplicate of [How do I compare strings in Java?](https://stackoverflow.com/questions/513832/how-do-i-compare-strings-in-java) — George Z., Mar 27 '19 at 11:55

score 0 · Answer 1 · answered Mar 28 '19 at 07:00

0

you can add item listener here and then check for selected item, depends on that you can make visible your panel or show dialog box.

answered Mar 28 '19 at 07:00

Kaushik Galiya

19
3

Implementing new window on combo box

1 Answers1