Bash - Counter for multiple parameters in file

Question

I created a command, which works, but not exactly as I want. So I would like to upgrade this command to right output.

My command:

awk '{print $1}' ios-example.com.access | sort | uniq -c | sort -nr

Output of my command:

8 192.27.69.191
2 82.202.69.253

Input file: https://pajda.fit.vutbr.cz/ios/ios-19-1-logs/blob/master/ios-example.com.access.log

Output I need(hashtags instead of numbers):

198.27.69.191 (8): ########
82.202.69.253 (2): ##

@Zakys98 I see you are new here, but it is best to give us sample of input. I assumed that numbers in front were from input (8 and 2), but they came from `uniq -c` haven't they? — , Mar 27 '19 at 18:23

kvantour · Answer 1 · 2019-03-27T18:04:17.043

0

You can upgrade your command by adding another awk to the list, or you can just use a single awk for the whole thing:

awk '{a[$1]++}
     END { for(i in a) { 
             printf "%s (%d):" ,i,a[i]
             for(j=0;j<a[i];++j) printf "#"; printf "\n"
           }
     }' file

edited Mar 27 '19 at 18:04

answered Mar 27 '19 at 17:26

kvantour

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The output is: not enough arguments to satisfy format string – Zakys98 Mar 27 '19 at 17:51
@Zakys98 sorry missed a comma – kvantour Mar 27 '19 at 18:04
where ? i dont see it – Zakys98 Mar 27 '19 at 18:23
@Zakys98 it was in the first printed statement but already corrected – kvantour Mar 27 '19 at 18:27
yes, but i dont see what you have just repaired and i wanna know – Zakys98 Mar 27 '19 at 18:28
@Zakys98 the comma before the `i` was missing. Printf was expecting 2 args but received only one. The missing comma made awk interprete `"%s (%d):" i` as a string concatenation. – kvantour Mar 27 '19 at 18:48

score 0 · Answer 2 · answered Mar 27 '19 at 17:57

Using xargs with sh and printf. Comments in between the lines. Live version at tutorialspoint.

# sorry cat
cat <<EOF |
8 192.27.69.191
2 82.202.69.253
EOF
# for each 2 arguments
xargs -n2 sh -c '
    # format the output as "$2 ($1): "
    printf "%s (%s): " "$2" "$1"
    # repeat the character `#` $1 times
    seq "$1" | xargs printf "#%.0s"
    # lastly a newline
    printf "\n"
' --

I think we could shorten that a bit with:

xargs -n2 sh -c 'printf "%s (%s): %s\n" "$2" "$1" $(printf "#%.0s" $(seq $1))' --

or maybe just echo, if the input is sufficiently safe:

xargs -n2 sh -c 'echo "$2 ($1): $(printf "#%.0s" $(seq $1))"' --

user3469811 · Accepted Answer · 2019-03-27T18:19:38.597

0

cat ios-example.com.access | sort | uniq -c | awk 'ht="#"{for(i=1;i<$1;i++){ht=ht"#"} str=sprintf("%s (%d): %s", $2,$1, ht); print str}'

expecting file with content like:

ipadress1
ipadress1
ipadress1
ipadress2
ipadress2
ipadress1
ipadress2
ipadress1

edited Mar 27 '19 at 18:19

answered Mar 27 '19 at 18:12

user3469811

676
1
5
17

That's a [useless use of `cat`](https://stackoverflow.com/questions/11710552/useless-use-of-cat) – tripleee Sep 20 '22 at 10:29

Bash - Counter for multiple parameters in file

3 Answers3