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I have two numbers -

3.125000 Mbytes and 2.954880 Mbytes.

I want to compare them and it should return True since they are almost 3Mbytes. How can I do so in Python3.

I tried doing math.isclose(3.125000,2.954880, abs_tol=0.1).

However, this returns False. I really don't understand how to put tolerance here. 

math.isclose(3.125000,2.954880,  abs_tol=0.1).

https://docs.python.org/3/library/math.html

math.isclose(a, b, *, rel_tol=1e-09, abs_tol=0.0)

I am using Python 3.5.2.

The expected result is True. The actual result is False.

ShadowRanger
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Prawn Hongs
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2 Answers2

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Your absolute tolerance is set to 0.1, so the difference would have to be less than 0.1 to consider them equal; 3.125000 - 2.954880 is (rounded) 0.17012, which is too big.

If you want them to be considered close, increase your tolerance a bit, e.g.:

math.isclose(3.125000, 2.954880, abs_tol=0.2)

which returns True as you expect.

ShadowRanger
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The function math.isclose is really meant for dealing with floating-point imprecisions. You can use it for this, but you need to tune it appropriately: the numbers in your example are more than 0.1 apart.

If you're not worried about floating-point imprecisions, the better way to compare them is the obvious one:

def equivalent(a, b):
    return abs(a-b) < 0.1
Draconis
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  • It uses both, but it's considered "close" if *either* threshold is met; passing `abs_tol` of 0.1 is roughly equivalent to what you wrote, but would *also* allow truly huge numbers with small relative differences to be considered close as well. – ShadowRanger Mar 27 '19 at 20:30
  • @ShadowRanger Yep, realized my mistake when I saw your answer. Edited so as not to mislead OP. – Draconis Mar 27 '19 at 20:30