Converting to manipulatable datetime format

Question

I have a date value 20130312 and I would like to convert it into a format like 2013-03-12 or a similar format

I've tried looking into the datetime library but could not find a solution.

Thanks in advance

datetime.strptime, datetime.strftime – G_M Mar 29 '19 at 02:15 — G_M, Mar 29 '19 at 02:15
https://stackoverflow.com/a/10624968/1189040 – Himal Mar 29 '19 at 02:16 — Himal, Mar 29 '19 at 02:16

score 2 · Accepted Answer · answered Mar 29 '19 at 02:16

2

I think you are looking for datetime.strptime:

from datetime import datetime

print(datetime.strptime('20130312', '%Y%m%d'))

For info on the pattern used, see here.

answered Mar 29 '19 at 02:16

iz_

1 Answers1