function .. takes 0 positional arguments but 1 was given

Question

I am new to Python and I want to practice a parent and derived class. I want to call parent function to the child class using super. But I got some error. Code is

class First:
    def my_func():
        print('first')

class Second(First):
    def my_func1():
        super().my_func()
        print('second')

obj = Second()
obj.my_func1()

read https://stackoverflow.com/questions/2709821/what-is-the-purpose-of-self — eyllanesc, Mar 29 '19 at 03:45

score 2 · Answer 1 · answered Mar 29 '19 at 03:46

2

class First:
    def my_func(self):
        print('first')

class Second(First):
    def my_func1(self):
        super().my_func()
        print('second')

obj = Second()
obj.my_func1()

answered Mar 29 '19 at 03:46

Hari

31
1
3

function .. takes 0 positional arguments but 1 was given

1 Answers1