How to get list of pattern string and matcher string in java regex

Question

First time I use Regex statement.

I have java regex statement, which split String by pattern with list of some characters.

String line = "F01T8B02S00003H04Z05C0.12500";
Pattern pattern = Pattern.compile("([BCFHSTZ])");
String[] commands = pattern.split(line);

for (String command : commands) {
 System.out.print(command);
}

output of above code is like (018020000304050.12500)

Actually I want output like this, ("F", "01", "T", "8", "B", "02", "S", "00003", "H", "04", "Z", "05", "C", "0.12500").

Means desired output is contains pattern character and split value both.

Can you please suggest me?

No. It may be some part missing. Like "F01B02S00003H04Z05C0.12500" — Bhavin S., Mar 29 '19 at 14:00
Yes, I got desired output, But i have to change regex statement. Thanks lot. — Bhavin S., Mar 30 '19 at 05:59

Skizo-ozᴉʞS ツ · Answer 1 · 2019-03-29T14:23:56.537

I've created a sample, try it and let me know if it's what you want.

public class Main {

public static void main(String[] args) {

    String line = "F01T8B02S00003H04Z05C0.12500";
    String pattern = "([A-Z][a-z]*)(((?=[A-Z][a-z]*|$))|\\d+(\\.\\d+)?)";

    Pattern r = Pattern.compile(pattern);

    Matcher m = r.matcher(line);
    HashMap<String, String> mHash = new LinkedHashMap<>();

    while (m.find()) {
        mHash.put(m.group(1), m.group(2));
    }

    System.out.println(mHash.toString());

}

}

Output is:

Edit with LinkedHashMap

public class Main {

    public static void main(String[] args) {

        String line = "F01T8B02S00003H04Z05C0.12500";
        String pattern = "([A-Z][a-z]*)(((?=[A-Z][a-z]*|$))|\\d+(\\.\\d+)?)";

        Pattern r = Pattern.compile(pattern);

        Matcher m = r.matcher(line);
        HashMap<String, String> mHash = new LinkedHashMap<>();

        while (m.find()) {
            mHash.put(m.group(1), m.group(2));
        }

        System.out.println(mHash.toString());

    }
}

Output is :

{F=01, T=8, B=02, S=00003, H=04, Z=05, C=0.12500}

score 2 · Accepted Answer · answered Mar 29 '19 at 14:48

You can use a String#split on [A-Z] which keeps the delimiter as separated item:

String line = "F01T8B02S00003H04Z05C0.12500";
String[] result = line.split("((?<=[A-Z])|(?=[A-Z]))");

System.out.println(java.util.Arrays.toString(result));

Which will result in the String-array:

[F, 01, T, 8, B, 02, S, 00003, H, 04, Z, 05, C, 0.12500]

Try it online.

score 0 · Answer 3 · answered Mar 30 '19 at 06:03

Above all answer were correct. I got solution by below code also.

String line = "F01T8B02S00003H04Z05C0.12500A03";

String[] commands = line.split("(?<=[BCFHSTZ])|(?=[BCFHSTZ])");

for (String str: commands) {
    System.out.print(str);
}

Thanks all for help.

How to get list of pattern string and matcher string in java regex

3 Answers3