How do I make a while loop break after one of two conditions is fulfilled?

Question

I'm making a simple turn-based fighting game in Python 3. My while loop won't finish when the health of the computer is 0 or below.

I couldn't find any posts answering my problem. I have tried some different kinds of conditions but it either stops before the loop or doesn't stop.

from random import randint

def punch():
    return randint(18, 25)

c_health = 100
p_health = 100


while(c_health and p_health > 0):

    move = input("Pick a move (punch, kick or heal): ").lower()

    if move == "punch":
        damage = punch()
        c_health = c_health - damage
        print(f"You have dealt {damage} dmg.")
        print(f"The computer has {c_health} health.")


    elif move == "kick":
        print(kick())

    elif move == "heal":
        print(heal())

I expect the while loop to finish when the c_health reaches 0 or below.

You need `c_health > 0 and p_health > 0` – Thierry Lathuille Mar 31 '19 at 21:18 — Thierry Lathuille, Mar 31 '19 at 21:18
`while(c_health > 0 and p_health > 0):` – Patrick Artner Mar 31 '19 at 21:18 — Patrick Artner, Mar 31 '19 at 21:18

score 2 · Accepted Answer · answered Mar 31 '19 at 21:18

2

while(c_health > 0 and p_health > 0):

answered Mar 31 '19 at 21:18

Kaue Silveira

170
3

FYI, parentheses around most boolean expressions generally aren't needed in Python. i.e. `while c_health > 0 and p_health > 0:` would work just as well. – martineau Mar 31 '19 at 21:23

How do I make a while loop break after one of two conditions is fulfilled?

1 Answers1