How do I print all the elements in my bash array?

Question

I am running this script in bash to add a list of user to an array and then write it to a file. This is the script:

echo "Insert the first user of the list"
read -r user_name
user_list=()
echo "User $user_name inserted!"
user_list+=($user_name)

echo "Do you want to insert another user?(yes or no)"
read -r answ
while [ $answ == "yes" ]; do
     echo "Enter a new user to insert"
     read -r new_user
     user_list+=($new_user)
     echo "Users list contains:"
     echo "$user_list"
     echo "Do you want to add another user?(yes or no)"
     read -r answ
done

echo "$user_list" > user_list.txt;

Everything works fine except that the array only contains the first element.I don't understand why the $new_user are not added to the array.

bash arrays only print the first element when called with their name. — jeremysprofile, Apr 01 '19 at 15:08

score 1 · Answer 1 · answered Apr 01 '19 at 15:14

1

Last line could be

printf "%s\n" "${user_list[@]}" >user_list.txt

answered Apr 01 '19 at 15:14

F. Hauri - Give Up GitHub

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How do I print all the elements in my bash array?

1 Answers1