Percent encoding output incorrect in Swift 4 for '(apostrophe)

Question

I am encoding my string to hit a web service. I am using addingPercentEncoding(withAllowedCharacters: CharacterSet) to encode my String.

Everything works fine except the '(apostrophe) character gets encoded to %E2%80%99 instead of %27.

    if let _keyword = keyword?
        .addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed) {
        parameters?["keyword"] = _keyword
    }

For Example:

When keyword is Maggie's, output = "Maggie%E2%80%99s" instead of "Maggie%27s".

Output is fine for others, when keyword is Jelly Extracts output is "Jelly%20Extracts".

So, how do I encode '(apostrophe) properly to %27

Edit: When I pass static text, like "Maggie's.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed)" output is correct but when I wrap it in a variable output comes incorrect.

apostrophe(') is a legal character in query. It needn't not or won't be encoded. — Rikesh Subedi, Apr 02 '19 at 09:44
For anyone running into this issue because apostrophe encoding doesn't work as expected, you're probably running into Smart Punctuation issues. Smart Punctuation replaces the symbol backtick (') with the apostrophe (’), which are two different characters. The apostrphe (’) encodes to %E2%80%99 whereas the symbol backtick encodes to %27. You can turn smart punctuation off on a per textfield basis via the `smartQuotesType` method. — Alex Sullivan, Jan 25 '21 at 14:11

Daniil Subbotin · Answer 1 · 2019-04-02T10:27:53.827

0

Instead of urlQueryAllowed use alphanumerics.

let originalString = "Maggie's"
let escapedString = originalString.addingPercentEncoding(withAllowedCharacters: .alphanumerics)
print(escapedString) // Optional("Maggie%27s")

edited Apr 02 '19 at 10:27

answered Apr 02 '19 at 09:39

Daniil Subbotin

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This doesn't work – udbhateja Apr 02 '19 at 10:20
It works. I check it in Playgrounds. – Daniil Subbotin Apr 02 '19 at 10:27
`let data = keyword!.addingPercentEncoding(withAllowedCharacters: .alphanumerics) let test = "Uday's".addingPercentEncoding(withAllowedCharacters: .alphanumerics)` Works fine when I pass static test but fails when I pass it in a variable – udbhateja Apr 02 '19 at 11:09
I set keyword as `let keyword: String? = "Uday's"` and it works well. – Daniil Subbotin Apr 02 '19 at 11:49

Percent encoding output incorrect in Swift 4 for '(apostrophe)

1 Answers1