getFromLocationName() returns null on android tablet

Question

cmap.setOnClickListener(new OnClickListener()
        {
            public void onClick(View v)
            {   System.out.println("Cmap initial:=lat:-"+lat+" lang:-"+lon);
            Toast t=Toast.makeText(getBaseContext(),"Location"+lat+"lang:-"+lon,Toast.LENGTH_LONG);
            t.show();
            tlname=elname.getText().toString();
            tladdr=eladdr.getText().toString();
            addressInput=tlname+" "+tladdr;
            System.out.println("address:-"+addressInput);
            Toast t3=Toast.makeText(getBaseContext(),"Address"+addressInput,Toast.LENGTH_LONG);
            t3.show();
            try
            {
                Geocoder gc1 = new Geocoder(
                        getBaseContext(), Locale.getDefault());

                foundAdresses = gc1.getFromLocationName(addressInput, 5);
                showAdressResults.sendEmptyMessage(0);
                Toast t1=Toast.makeText(getBaseContext(),"Location...."+foundAdresses,Toast.LENGTH_LONG);
                t1.show();
                System.out.println("faddress:-"+foundAdresses);
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            if (foundAdresses.size() == 0)
            { // if no address found,
                // display an error
                Dialog locationError = new AlertDialog.Builder(
                        Gotask.this).setIcon(0).setTitle(
                        "Error").setPositiveButton(R.string.ok, null)
                        .setMessage(
                        "Sorry, your address doesn't exist.")
                        .create();
                locationError.show();

            } else 
            { // else display address on map
                for (int i = 0; i < foundAdresses.size(); ++i)
                {

                    Address x = foundAdresses.get(i);
                    lat =  (x.getLatitude() *100);
                    lon = (float) x.getLongitude();
                    System.out.println("Cmap:=lat:-"+lat+" lang:-"+lon);


                }
                navigateToLocation((lat * 1000000), (lon * 1000000),myMap);
            }


        }

    });

try { Geocoder gc1 = new Geocoder(getBaseContext(), Locale.getDefault()); foundAdresses = gc1.getFromLocationName(addressInput, 5); showAdressResults.sendEmptyMessage(0); } catch (IOException e){e.printStackTrace(); }if (foundAdresses.size() == 0){err0r msg} else { for (int i = 0; i < foundAdresses.size(); ++i) {Address x = foundAdresses.get(i); lat = (x.getLatitude() *100); lon = (float) x.getLongitude(); }navigateToLocation((lat * 1000000), (lon * 1000000),myMap); — monika, Apr 05 '11 at 11:21

Girish Bhutiya · Answer 1 · 2012-09-13T10:49:54.303

1

I have also faced this kind of issue in reverse Geo coding so i am use Google api for it. Refer this link for google api to use in reverse geocoding.

edited Sep 13 '12 at 10:49

answered Jan 26 '12 at 12:52

Girish Bhutiya

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score 0 · Answer 2 · edited May 23 '17 at 11:55

I faced the same problem when i was developing an app based on google maps.The problem was with the devcie ,the one which i am using did't support backend service(a kind of service comes with device) which is responsible for working of GeoCoding related APIs.So i decided to use services exposed by google to query for lat & longitude for the required Address.So just give a try.

Refer this link to know more

http://code.google.com/apis/maps/documentation/geocoding/

Please refer following links:

How can you tell when an Android device has a Geocoder backend service?

Android; Geocoder, why do I get "the service is not available"?

Here is a sample request for geocoding request to obtain Latitude and longitude from response after parsing Xml output.

http://maps.googleapis.com/maps/api/geocode/xml?address=1600+Amphitheatre+Parkway,+Mountain+View,+CA&sensor=true_or_false

There is a clear cut example in the link mentioned earlier.

getFromLocationName() returns null on android tablet

2 Answers2