Unable to run schedular cron expression with 7 fields

Question

@Scheduled(cron = "0/20 * * * * ? 2005")
    public void execute(){
        System.out.println("ITs running...");
    }

Encountered invalid @Scheduled method 'execute': Cron expression must consist of 6 fields (found 7 in "0/20 * * * * ? 2005")

When I am trying to use 7 fields within the cron expression I am getting this error. Could anyone help me to resolve this issue please?

see this answer- https://stackoverflow.com/a/32521238/8098322 — Onkar Musale, Apr 04 '19 at 10:01

score 3 · Accepted Answer · answered Apr 04 '19 at 10:02

3

@Scheduled supports six fields when using cron expression. As per CronSequenceGenerator docs it doesn't support a year field:

The pattern is a list of six single space-separated fields: representing second, minute, hour, day, month, weekday. Month and weekday names can be given as the first three letters of the English names.

answered Apr 04 '19 at 10:02

Karol Dowbecki

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thanks you. But is there any other way to make use of year field in the cron expression? – preetk Apr 13 '19 at 16:06
@preetk not with `@Scheduled` unless you plan to fork Spring and add the support yourself – Karol Dowbecki Apr 13 '19 at 16:17
1

Example Unix Format: 0 56 8 1/1 * * * Example Spring Format: 0 56 8 1/1 * * – Brain Jan 03 '20 at 07:58

Unable to run schedular cron expression with 7 fields

1 Answers1