Compare two dicts and update the dict based on the compared dict

Question

Solution for Compare two dict and update the dict based on compared dict

compare dict1 with dict2 and update the dict1 based on the dict key values,here "id" is the unique key

dict1={id:1,mobile:'nokia',count:54,size:9}

dict2={id:1,mobile:'nokia',count:63,size:9}

expected output:

dict1={id:1,mobile:'nokia',count:63,size:9}

What should the comparison do? This is probably just `dict1.update(dict2)`. — RemcoGerlich, Apr 05 '19 at 10:04
Before comparing these dict,Need to iterate the the "id" which means check the "dict1" id= "dict" id and update the "dict1" values from "dict2" — Vivek M Vijay, Apr 05 '19 at 10:09
Possible duplicate of [How to merge two dictionaries in a single expression?](https://stackoverflow.com/questions/38987/how-to-merge-two-dictionaries-in-a-single-expression) — Jondiedoop, Apr 05 '19 at 10:10

score 0 · Answer 1 · answered Apr 05 '19 at 10:08

0

Sample Code:

dict1={"id":1,"mobile":'nokia',"count":54,"size":9}

dict2={"id":1,"mobile":'nokia',"count":63,"size":9}

dict1.update(dict2)

print(dict1)

Output:

{'id': 1, 'mobile': 'nokia', 'count': 63, 'size': 9}

answered Apr 05 '19 at 10:08

Anonymous

1 Answers1