converting integer to string C++

Question

I am trying to convert an integer to char array and I came across this piece of code

int i = 5;
std::string s;
std::stringstream out;
out << i;
s = out.str();

But when I try to print the value of s it still prints 5. I don't know if its supposed to do that or am I doing something wrong? Besides I would prefer if I could convert the same int to char array. But I would appreciate any help in the matter. Thanks! Code taken from: Alternative to itoa() for converting integer to string C++?

What do you want it to print? The textual representation of the number 5 is "5". — James Kanze, Apr 05 '11 at 17:06
I was just trying to see what the textual representation would be. Does this mean if I try to convert any large numbers to text they would still be the same numbers? For example if I've -635997, what would that look like? Because right now it gives me same number — Max Eastman, Apr 05 '11 at 17:09
What else could it be? What is the textual representation of -635997, if not "-635997"? A given number has many possible textual representations; by default, you get the simplest and most familiar (decimal, no leading 0's). There are flags you can set to get other representations. — James Kanze, Apr 06 '11 at 08:54

score 4 · Answer 1 · answered Apr 05 '11 at 17:07

Yes, it's supposed to do that. You'd (primarily) notice the difference from just printing a number out directly if you do some other string-type manipulation on the result (e.g., concatenating it with other strings, searching for characters in the string).

Just for example:

std::cout << i+i;   // should print "10"
std::cout << s+s;   // should print "55"

Mahesh · Accepted Answer · 2011-04-05T17:58:12.770

1

Besides I would prefer if I could convert the same int to char array.

char *charPtr = new char[ s.length() + 1 ] ; // s is the string in the snippet posted
strcpy( charPtr, s.c_str() ) ;

// .......

delete[] charPtr ; // Should do this, else memory leak.

edited Apr 05 '11 at 17:58

answered Apr 05 '11 at 17:11

Mahesh

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just wondering shouldn't the argument to strlen() be a char pointer? or would the string act the same way? – Max Eastman Apr 05 '11 at 17:21
@Max Eastman : No, you're correct -- passing a `std::string` to `strlen` is illegal. It should be `new char[s.length() + 1];` or `new char[strlen(s.c_str()) + 1];`, but of course the second one is inherently less efficient. – ildjarn Apr 05 '11 at 17:41
@ildjarn - You are correct. Time for me to take rest, I guess :) – Mahesh Apr 05 '11 at 17:51
1

@Mahesh : `std::auto_ptr` uses `delete` rather than `delete []`, so `std::auto_ptr` would cause undefined behavior here. On C++0x compilers `std::unique_ptr` would be preferred; on older compilers, `boost::scoped_array` or `boost::shared_array` are the best options. – ildjarn Apr 05 '11 at 17:54
@Mahesh : Speaking of which, your code should have `delete [] charPtr;` rather than `delete charPtr;` ;-] – ildjarn Apr 05 '11 at 17:57
@ildjarn - Really, I am signing off for the day. – Mahesh Apr 05 '11 at 17:58

score 1 · Answer 3 · answered Apr 05 '11 at 18:16

If you would like to stop worrying about issues like that you might be interested in boost/lexical_cast.hpp.

#include <boost/lexical_cast.hpp>
#include <string>
#include <iostream>

int main() {
  const int i=5;
  const char* s = boost::lexical_cast<std::string>(i).c_str();
  std::cout << s << std::endl;
}

converting integer to string C++

3 Answers3

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