Python String to array in form

Question

I cant create like [12,34,56,78]

I tried used list(),but can't get the answer.

A=12345678,list(A)=[1,2,3,4,5,6,7,8]

i need the result like 12345678=[12,34,56,78].Any answer?

Possible duplicate here : https://stackoverflow.com/questions/21270320/turn-a-single-number-into-single-digits-python — MelKoutch, Apr 08 '19 at 14:29
How is this a different format ? Because it's a pair of number instead of single digits ? Please, explain clearly your problem. — MelKoutch, Apr 08 '19 at 14:33
Possible duplicate of [Splitting integer in Python?](https://stackoverflow.com/questions/1906717/splitting-integer-in-python) — S.K. Venkat, Apr 08 '19 at 14:42

DirtyBit · Answer 1 · 2019-04-08T14:36:27.210

1

Perhaps:

A = '12345678'

print([int(A[x:x+2]) for x in range(0, len(A), 2)])

OUTPUT:

[12, 34, 56, 78]

edited Apr 08 '19 at 14:36

answered Apr 08 '19 at 14:30

DirtyBit

Frenchy · Accepted Answer · 2019-04-08T14:46:12.567

0

you could try:

s = '12345678'
n = 2
result=[s[i:i + n] for i in range(0, len(s), n)]
print(result)

['12', '34', '56', '78']

edited Apr 08 '19 at 14:46

answered Apr 08 '19 at 14:30

Frenchy

Yes,you are right. – Kai Long Apr 08 '19 at 14:36
The output from this snippet is wrong, it'd be `['12', '34', '56', '78']` instead and not `[12, 34, 56, 78]` since you are not converting them to int. – DirtyBit Apr 08 '19 at 14:44
@ DirtyBit thank to point my typo error, – Frenchy Apr 08 '19 at 14:46

2 Answers2