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stars must be printed at the positions i have used but invalid syntax error is coming

# printing star in a heart shape format
for row in range(0,6):
    for colu in range(0,7):
        if row==0 and colu%3!==0:
            print('*',end=='')
        elif row==1 and colu%3==0:
            print('*',end=='')
        elif row-colu==2:
            print('*',end=='')
        elif row+colu==8:
            print('*',end=='')
        else:
            print(' ',end=='')
Aran-Fey
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at K2
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3 Answers3

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replace if row==0 and colu%3!==0 by 

if row==0 and colu%3!=0
Bharath
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0

As others have said, you need to replace !== with !=. However, you also need to change end== to end=.

Ecko
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0

This:

if row==0 and colu%3!==0:

Should be like this:

if row == 0 and colu % 3 != 0:

And all of the end==, should be in the form end=

 

So all together:

for row in range(0, 6):
    for colu in range(0, 7):
        if row == 0 and colu % 3 != 0:
            print('*', end='')
        elif row == 1 and colu % 3 == 0:
            print('*', end='')
        elif row - colu == 2:
            print('*', end='')
        elif row + colu == 8:
            print('*', end='')
        else:
            print(' ', end='')
ruohola
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  • While I agree that `!==` should be `!=` and `end==` should be `end=`, it is not strictly necessary to have whitespace in between operators. `if row==0 and colu%3!=0:` is valid syntax, albeit not idiomatically styled. – Kevin Apr 09 '19 at 13:57
  • @Kevin very true, that's why I didn't say that the lack of whitespace was a problem. I just habitually corrected the code to have cleaner whitespace usage. – ruohola Apr 09 '19 at 13:59