How I make approximation for a large 5, numbers C# code

Question

How I make approximation for a large 5, numbers C# code example

62     I want to get 65 
63     get   65
71.15  get  75

Obtain the digits first. Use ```n % 10``` to obtain the first (right-moist) digit. The, ```n/10``` will return the other digits plus a reminder. Eliminate the reminder with the equivalent in C# for ```Math.floor``` — acarlstein, Apr 09 '19 at 19:54
Possible duplicate of [Round a number to the next HIGHEST 10](https://stackoverflow.com/questions/8679697/round-a-number-to-the-next-highest-10) — devNull, Apr 09 '19 at 20:00

Johnny · Answer 1 · 2019-04-09T20:08:16.807

2

Try something like this:

Math.Round(x - x % 5) + 5

edited Apr 09 '19 at 20:08

answered Apr 09 '19 at 19:52

Johnny

@WeatherVane understand your concert but since it is 5 should not be a problem... – Johnny Apr 09 '19 at 20:00
I was thinking of the `71.15` but also of C (tag was removed). – Weather Vane Apr 09 '19 at 20:01
@WeatherVane, I added rounding to the nearest integer – Johnny Apr 09 '19 at 20:08
Yes, but the input `71.15` is a floating point number, and in C at least, `x % 5` is a syntax error for `float x` or `double x`. One would use `fmod`. – Weather Vane Apr 09 '19 at 20:10

score 1 · Answer 2 · answered Apr 09 '19 at 19:55

1

answered Apr 09 '19 at 19:55

Weather Vane

Amir Molaei · Answer 3 · 2019-04-09T20:01:48.803

0

One solution:

double num = 64.65;
double nextMultiplyOf5 = (int)(num + 4) / 5 * 5;

edited Apr 09 '19 at 20:01

answered Apr 09 '19 at 19:53

Amir Molaei

3 Answers3