How to print the second word of each line in a text file?

Question

I have a text file and the lines of text are divided by three strings. How can I print just the second word?

I've tried to print after the blank space (" "), but is not working as supossed to.

The next code prints the first word of each line:

void leerEmpleados(){
    FILE *fp;
    struct empleados{
        char codigo[6];
        char nombre[20];
        char apellido[20];
        char departamento[20];
    };

    struct empleados emp;

    fp = fopen("Empleado.txt", "r");
    if (fp == NULL) {
        printf("El archivo no existe");
    } else {
        //Lee los códigos
        while (!feof(fp)) {
            fscanf(fp,"%s%*[^\n]",emp.codigo);
            printf("%s\n",emp.codigo);
        }

    }
    fclose(fp);
}

The file data can contain something like this: 102 John Musician'\n' 103 Paul Musician'\n' 104 Ringo Musician

Please edit the question, and show an example of the file data — OldProgrammer, Apr 09 '19 at 20:24
Please read [Why is “while (!feof(file))” always wrong?](https://stackoverflow.com/questions/5431941/why-is-while-feof-file-always-wrong) — Mark Benningfield, Apr 09 '19 at 20:26
What do you call a string in that file? Do you mean a sentence? From your sample data you might even mean a single word. Please clarify. — Gerhardh, Apr 10 '19 at 05:37
@Gerhardh Yes, I mean a single word. I insert the word as a string that's why I say "string", but you're right. — Vinicio López, Apr 10 '19 at 22:23

score 0 · Accepted Answer · answered Apr 09 '19 at 20:50

0

Change your format string to " %*s%s%*[^\n]". %*s reads the first word on the line and discards it, then %s reads the second word.

answered Apr 09 '19 at 20:50

Barmar

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How to print the second word of each line in a text file?

1 Answers1