How to specify a NonSerialized field with public accessors for XML Serialization

Question

How do you specify a NonSerialized field with public accessors for XML Serialization?

[NonSerialized]
public String _fooBar;
//Declaring the property here will serialize the _fooBar field
public String FooBar
{
    get { return _fooBar; }
    set { _fooBar = value; }
}

I assume this is a made up example? Otherwise you can just use an auto property and mark that as `NonSerialized`. — BrokenGlass, Apr 06 '11 at 01:33
@BrokenGlass I actually get "Attribute 'NonSerialized' is not valid on this declaration type. It is only valid on 'field' declarations." on an auto-property... — MPelletier, Apr 06 '11 at 01:36
@BrokenGlass - `[XmlIgnore]` works with auto-properties, though. — MPelletier, Apr 06 '11 at 01:42
@MPelletier: Would have been good to know you are looking for *XML serialization* from the beginning - kudos to @Hans for catching it. — BrokenGlass, Apr 06 '11 at 01:44
@BrokenGlass - I just, very naively, discovered that it made a difference. My bad. — MPelletier, Apr 06 '11 at 01:49
Glad you got it resolved - and we both learnt something in the process ;-) — BrokenGlass, Apr 06 '11 at 01:51

score 17 · Accepted Answer · edited Nov 20 '14 at 18:29

17

Properties don't get serialized by BinaryFormatter, only fields. The [NonSerialized] attribute has no meaning for XML serialization. Use [XmlIgnore] instead.

edited Nov 20 '14 at 18:29

MPelletier

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answered Apr 06 '11 at 01:34

Hans Passant

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How to specify a NonSerialized field with public accessors for XML Serialization

1 Answers1