How to split a string in format AB123 --> AB 123? Java

Question

I have a string in format AB123. I want to split it between the AB and 123 so AB123 becomes AB 123. The contents of the string can differ but the format stays the same. Is there a way to do this?

Answer 1

Following up with the latest information you provided (2 letters then 3 numbers):

myString.subString(0, 2) + " " + myString.subString(2)

What this does: you split your input string myString at the 2nd character and append a space at this position.

Answer 2

Explanation: \D represents non-digit and \d represents a digit in a regular expression and I used ternary operation in the regex to split charter to the number.

  String string = "AB123";
  String[] split = string.split("(?<=\\D)(?=\\d)");
  System.out.println(split[0]+" "+split[1]);

Answer 3

Try

String a = "abcd1234";
int i;
for(i = 0; i < a.length(); i++){
    char c = a.charAt(i);
    if( '0' <= c && c <= '9' )
        break;
}
String alphaPart = a.substring(0, i);
String numberPart = a.substring(i);

Hope this helps

Answer 4

Although I would personally use the method provided in @RakeshMothukur's answer, since it also works when the letter or digit counts increase/decrease later on, I wanted to provide an additional method to insert the space between the two letters and three digits:

String str = "AB123";
StringBuilder sb = new StringBuilder(str);
sb.insert(2, " "); // Insert a space at 0-based index 2; a.k.a. after the first 2 characters
String result = sb.toString(); // Convert the StringBuilder back to a String

Try it online.

Answer 5

Here you go. I wrote it in very simple way to make things clear.

What it does is : After it takes user input, it converts the string into Char array and it checks single character if its INT or non INT. In each iteration it compares the data type with the prev character and prints accordingly.

Alternate Solutions

1) Using ASCII range (difficulty = easy)

2) Override a method and check 2 variables at a time. (difficulty = Intermediate)

import org.omg.CORBA.INTERNAL;

import java.io.InputStreamReader;
import java.util.*;
import java.io.BufferedReader;


public class Main {

    public static void main(String[] args) throws Exception {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        char[] s = br.readLine().toCharArray();
        int prevflag, flag = 0;
        for (int i = 0; i < s.length; i++) {
            int a = Character.getNumericValue(s[i]);
            String b = String.valueOf(s[i]);
            prevflag = flag;
            flag = checktype(a, b);
            if ((prevflag == flag) || (i == 0))
                System.out.print(s[i]);
            else
                System.out.print(" " + s[i]);
        }
    }

    public static int checktype(int x, String y) {
        int flag = 0;
        if (String.valueOf(x).equals(y))
            flag = 1; // INT
        else
            flag = 2; // non INT
        return flag;

    }
}

Answer 6

I was waiting for a compile to finish before heading out, so threw together a slightly over-engineered example with basic error checking and a test.

import java.text.ParseException;
import java.util.LinkedList;

public class Main {

    static public class ParsedData {
        public final String prefix;
        public final Integer number;

        public ParsedData(String _prefix, Integer _number) {
            prefix = _prefix;
            number = _number;
        }

        @Override
        public String toString() {
            return prefix + "\t" + number.toString();
        }

    }

    static final String TEST_DATA[] = {"AB123", "JX7272", "FX402", "ADF123", "JD3Q2", "QB778"};

    public static void main(String[] args) {
        parseDataArray(TEST_DATA);
    }

    public static ParsedData[] parseDataArray(String[] inputs) {
        LinkedList<ParsedData> results = new LinkedList<ParsedData>();
        for (String s : TEST_DATA) {
            try {
                System.out.println("Parsing: " + s);
                if (s.length() != 5) throw new ParseException("Input Length incorrect: " + s.length(), 0);
                String _prefix = s.substring(0, 2);
                Integer _num = Integer.parseInt(s.substring(2));
                results.add(new ParsedData(_prefix, _num));
            } catch (ParseException | NumberFormatException e) {
                System.out.printf("\"%s\", %s\n", s, e.toString());
            }
        }
        return results.toArray(new ParsedData[results.size()]);
    }
}