I'm fetching data from AllContacts; in that data I'm getting contact details such as (998) 989-8989. Using this number, I'm not able to make a call. Can any one help out with this? Thanks in advance.
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HI All
At last i have used this following code to resolve this issue
NSString *originalString = @"(998) 989-8989";
NSMutableString *strippedString = [NSMutableString
stringWithCapacity:originalString.length];
NSScanner *scanner = [NSScanner scannerWithString:originalString];
NSCharacterSet *numbers = [NSCharacterSet
characterSetWithCharactersInString:@"0123456789"];
while ([scanner isAtEnd] == NO) {
NSString *buffer;
if ([scanner scanCharactersFromSet:numbers intoString:&buffer]) {
[strippedString appendString:buffer];
} else {
[scanner setScanLocation:([scanner scanLocation] + 1)];
}
}
NSLog(@"%@", strippedString);
Thanks All

siva
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Sounds like you can just remove spaces, brackets and hypens.
NSString *phoneNumber = @"(998) 989-8989";
phoneNumber = [phoneNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
phoneNumber = [phoneNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
phoneNumber = [phoneNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
phoneNumber = [phoneNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
phoneNumber = [@"tel://" stringByAppendingString:phoneNumber];
[[UIApplication sharedApplication] openURL:phoneNumber];

Zaky German
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Thanks dude ,but in different countries they will have different format of calling the phone numbers.In that way it will create a problem again :( – siva Apr 07 '11 at 09:15