How to convert time into word form in Python?

Question

I am trying to convert inputted time into word format using functions.

I tried asking input for the hour and min separate, then covering the number to appropriate word. Also, being sure the hr doesn't exceed 12 and the min doesn't exceed 59. Here is what I have so far.

def main() :
   timeHour = int(input("Please enter current hour: "))
   timeMin = int(input("Please enter your current minitues: "))
   print(intName(timeHour, timeMin))

## Turns a number into its English name
#
def intName(timeHour, timeMin) :
   name = timeMin
   part = timeHour


   if name >= 59 :
      part == 'Invalid time, please try again!'
      name == ''
   if part > 12 or part < 1 :
      part == 'Invalid time, please try again!'
      name == ''
   else:
      name == ''

   return name

## Turns minutes into its English name

def minName(timeMin) :
   if number == 0 : return "o clock"
   if number == 1 : return "one"
   if number == 1 : return "one"
   if number == 2 : return "two"
   if number == 2 : return "two"
   if number == 3 : return "three"
   if number == 3 : return "three"
   if number == 4 : return "four"
   if number == 4 : return "four"
   if number == 5 : return "five"
   if number == 6 : return "six"
   if number == 7 : return "seven"
   if number == 8 : return "eight"
   if number == 9 : return "nine"
   if number == 10 : return "ten"
   if number == 11 : return "eleven"
   if number == 12 : return "twelve"
   if number == 13 : return "thirteen"
   if number == 14 : return "fourteen"
   if number == 15 : return "quarter after"
   if number == 16 : return "sixteen"
   if number == 17 : return "seventeen"
   if number == 18 : return "eighteen"
   if number == 19 : return "nineteen"
   if number == 20 : return "twenty"
   if number == 21 : return "twenty-one"
   if number == 22 : return "twenty-two"
   if number == 23 : return "twenty-three"
   if number == 24 : return "twenty-four"
   if number == 25 : return "twenty-five"
   if number == 26 : return "twenty-six"
   if number == 27 : return "twenty-seven"
   if number == 28 : return "twenty-eight"
   if number == 29 : return "twenty-nine"
   if number == 30 : return "thirty"
   return ""

## Turns minutes into its English name
def hourName(timeHour) :
   if digit == 1 : return 'one'
   if digit == 2 : return 'two'
   if digit == 2 : return 'two'
   if digit == 3 : return 'three'
   if digit == 3 : return 'three'
   if digit == 4 : return 'four'
   if digit == 4 : return 'four'
   if digit == 5 : return 'five'
   if digit == 6 : return 'six'
   if digit == 7 : return 'seven'
   if digit == 8 : return 'eight'
   if digit == 9 : return 'nine'
   if digit == 10 : return 'ten'
   if digit == 11 : return 'eleven'
   if digit == 12 : return 'twelve'
   return ''
# Start the program.
main()

I'm not sure what I am doing wrong here, any suggestions?

You are never calling the `hourName` or `minName` functions. — Josep Valls, Apr 12 '19 at 21:09

score 1 · Accepted Answer · answered Apr 12 '19 at 21:04

1

Try:

def intName(timeHour, timeMin) :
   name = timeMin
   part = timeHour


   if name >= 59 :
      return 'Invalid time, please try again!'
   if part > 12 or part < 1 :
      return 'Invalid time, please try again!'

   return hourName(timeHour) + ' ' + minName(timeMin)

answered Apr 12 '19 at 21:04

potato

36
5

Thanks SO much! It works! I also had to change "number ==" and "digit ==" to timeMin and timeHour because number and digit were not defined and not pulling from the input. – Klay Apr 12 '19 at 21:13

How to convert time into word form in Python?

1 Answers1