How to check whether two three dimensional numpy arrays are the same?

Question

I have a numpy array with shape (1,x,1) and the second one also with shape (1,x,1). I wonder how can I check whether they are the same? Examples:

1. First:

[[[ 2]
  [ 3]
  [ 4]
  [ 5]
  [ 6]
  [ 7]
  [ 8]
  [ 9]
  [ 4]
  [ 6]
  [10]]]

Second:

[[[ 2]
  [ 3]
  [ 4]
  [ 5]
  [ 6]
  [ 7]
  [ 8]
  [ 9]
  [ 4]
  [ 6]
  [10]]]

Response: True

2.

First:

[[[ 2]
  [ 3]
  [ 4]
  [ 5]
  [ 6]
  [ 7]
  [ 8]
  [ 9]
  [ 4]]]

Second:

[[[ 1]
  [ 2]
  [ 3]
  [ 5]
  [ 6]
  [ 2]
  [ 8]
  [ 3]
  [ 5]]]

Response: False

`np.allclose` is easy to use, and better if the arrays are floats. — hpaulj, Apr 13 '19 at 17:05
https://docs.scipy.org/doc/numpy/reference/generated/numpy.array_equal.html — Mark Setchell, Apr 13 '19 at 21:04

score 0 · Answer 1 · answered Apr 13 '19 at 17:00

0

There is already a SO question with that topic and a good answer by @Juh_ link.

The solution:

(A==B).all()

answered Apr 13 '19 at 17:00

Sebastian Dengler

`np.array_equal` will work, too? – thedbogh Apr 13 '19 at 17:02
Yes it should, it's also mentioned in the answer :) – Sebastian Dengler Apr 13 '19 at 17:06

1 Answers1