how to get slug of current url in current template

Question

In Django template, How to get the slug of the URL I am on in the template so that I can pass it to the template tag.

Example I am on: foo.com/slugname

then in the template, I am expecting

{% function|slugname%}

where 'function' is my template tag.

[link] https://stackoverflow.com/questions/2882490/how-to-get-the-current-url-within-a-django-template — HERAwais, Apr 14 '19 at 05:11
https://simpleisbetterthancomplex.com/tips/2016/07/20/django-tip-7-how-to-get-the-current-url-within-a-django-template.html — HERAwais, Apr 14 '19 at 05:14

score 4 · Accepted Answer · answered Apr 14 '19 at 17:07

4

Assuming your urlpattern for the view is something like this:

urlpatterns = [
    path("<slug>", views.SomeView.as_view(), name="some_name"),
]

you can get the slug's value to use in your template using request.resolver_match.kwargs.slug.

See also Django documentation on the HttpRequest objects and the ResolverMatch class.

answered Apr 14 '19 at 17:07

rafalmp

Thank you.It work properly ({% if request.resolver_match.kwargs.slug == 'slog_name'%} active {% endif %}) – Shaiful Islam Dec 05 '22 at 06:51

1 Answers1