Initialize std::array from initializer_list

Asked Apr 14 '19 at 11:29

Active Apr 14 '19 at 11:29

Viewed 38 times

I'm trying to initialise a member of type ::std::array<T,N>. However it doesn't take an initializer_list which I pass through the argument list. This boils down to:

#include <initializer_list>
#include <array>

int main() {
  ::std::initializer_list<int> il = {4,2};
  ::std::array<int,2> a = il; 
}

The array refuses to initialise from it. What is the intended way to cram data from an initializer_list into an std::array?

Note: I am compiling with C++17.

asked Apr 14 '19 at 11:29

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Strongly related: [How to construct std::array object with initializer list?](//stackoverflow.com/q/6893700) – Baum mit Augen Apr 14 '19 at 11:36
1

@BaummitAugen: Thanks. I couldn't find that question before. – bitmask Apr 14 '19 at 11:45
1

No worries. Another signpost won't hurt in this case. – Baum mit Augen Apr 14 '19 at 11:47

Initialize std::array from initializer_list

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