I'm trying to query some data in Postgres and I'm wondering how I might use some sort of pattern matching not merely to select rows - e.g. SELECT * FROM schema.tablename WHERE varname ~ 'phrase'
- but to select columns in the SELECT
statement, specifically doing so based on the common names of those columns.
I have a table with a bunch of estimates of rates over the course of many years - say, of apples picked per year - along with upper and lower 95% confidence intervals for each year. (For reference, each estimate and 95% CI comes from a different source - a written report, to be precise; these sources are my rows, and the table describes various aspect of each source. Based on a critique from below, I think it's important that the reader know that the unit of analysis in this relational database is a written report with different estimates of things picked per year - apples in one Table, oranges in another, pears in a third.)
So in this table, each year has three columns / variables:
rate_1994
low_95_1994
high_95_1994
The thing is, the CIs are mostly null - they haven't been filled in. In my query, I'm really only trying to pull out the rates for each year: all the variables that begin with rate_
. How can I phrase this in my SELECT
statement?
I'm trying to employ regexp_matches
to do this, but I keep getting back errors.
I've done some poking around StackOverflow on this, and I'm getting the sense that it may not even be possible, but I'm trying to make sure. If it isn't possible, it's easy to break up the table into two new ones: one with just the rates, and another with the CIs.
(For the record, I've looked at posts such as this one: Selecting all columns that start with XXX using a wildcard? )
Thanks in advance!