is there any way to choose more than 1 character by using charAt()

Question

 @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        TextView txt1 = (TextView) findViewById(R.id.txt1);
        TextView txt2 = (TextView) findViewById(R.id.txt2);
        TextView txt3 = (TextView) findViewById(R.id.txt3);
        TextView txt = (TextView) findViewById(R.id.txt4);
        String myStringValue = "Android programming is fun.";
        txt1.setText(myStringValue);
        txt2.setText(myStringValue.charAt(0) + "");
    }

i want to choose more than one character in charAt().

No. **charAt** takes one and only one character. But you can still extract a substring out of a string. — Phantômaxx, Apr 16 '19 at 08:22
No, then it wouldn't return a char. You could try getting a sub string if you wanted multiple characters. What are you trying to achieve exactly? — deadwards, Apr 16 '19 at 08:22
Possible duplicate of [Extract substring from a string](https://stackoverflow.com/questions/5414657/extract-substring-from-a-string) — Phantômaxx, Apr 16 '19 at 08:22

score 0 · Answer 1 · answered Apr 16 '19 at 08:52

charAt() always return one char. if you want more you must use other method or create loop for you purpose.

For example

    String myStringValue = "Android programming is fun.";
    StringBuilder textViewText = new StringBuilder();
    for(int i = 0 ; i< myStringValue.length();i++){
        if (i>=24 && i<=26){
            textViewText.append(myStringValue.charAt(i));
        }
    }
    Log.i("test",textViewText.toString());//print fun

Or use substring method

txt2.setText(myStringValue.substring(24,26) + "");//print fun

is there any way to choose more than 1 character by using charAt()

1 Answers1